qRound: do not expect failure on ARM64
Amend aa136d46e1 that changed qRound()
implementation to use __builtin_round() functions on ARM64 which do
not fail "round largest representable float less than 0.5" test,
unlike the simple version of qRound() used elsewhere.
Change-Id: Ic66cb0f826d91cd6a85ad72b646c79ded1c0eeca
Reviewed-by: Allan Sandfeld Jensen <allan.jensen@qt.io>
bb10
parent
1461df2ce4
commit
331fdee9dd
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@ -623,14 +623,18 @@ void tst_QGlobal::qRoundFloats() {
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QFETCH(float, actual);
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QFETCH(float, expected);
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#if !(defined(Q_PROCESSOR_ARM_64) && (__has_builtin(__builtin_round) || defined(Q_CC_GNU)) && !defined(Q_CC_CLANG))
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QEXPECT_FAIL("round largest representable float less than 0.5",
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"We know qRound fails in this case, but decided that we value simplicity over correctness",
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Continue);
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#endif
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QCOMPARE(qRound(actual), expected);
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#if !(defined(Q_PROCESSOR_ARM_64) && (__has_builtin(__builtin_round) || defined(Q_CC_GNU)) && !defined(Q_CC_CLANG))
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QEXPECT_FAIL("round largest representable float less than 0.5",
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"We know qRound fails in this case, but decided that we value simplicity over correctness",
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Continue);
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#endif
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QCOMPARE(qRound64(actual), expected);
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}
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@ -648,14 +652,18 @@ void tst_QGlobal::qRoundDoubles() {
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QFETCH(double, actual);
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QFETCH(double, expected);
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#if !(defined(Q_PROCESSOR_ARM_64) && (__has_builtin(__builtin_round) || defined(Q_CC_GNU)) && !defined(Q_CC_CLANG))
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QEXPECT_FAIL("round largest representable double less than 0.5",
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"We know qRound fails in this case, but decided that we value simplicity over correctness",
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Continue);
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#endif
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QCOMPARE(qRound(actual), expected);
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#if !(defined(Q_PROCESSOR_ARM_64) && (__has_builtin(__builtin_round) || defined(Q_CC_GNU)) && !defined(Q_CC_CLANG))
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QEXPECT_FAIL("round largest representable double less than 0.5",
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"We know qRound fails in this case, but decided that we value simplicity over correctness",
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Continue);
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#endif
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QCOMPARE(qRound64(actual), expected);
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}
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