whytofly
/
qt6-bb10
1
0
Fork 0
Code Issues Pull Requests Packages Projects Releases Wiki Activity

Make sure that QAccessibleWindowContainer::childCount is valid 

When embedding foreign windows, we won't be able to return a valid child
accessible interface, so do not report it at all.
Supporting foreign windows properly is platform specific and something
to consider, but at least we shouldn't crash.

Task-number: QTBUG-63451
Change-Id: I19350cf97dc8d0c3f3052411eba0eee5f750dbab
Reviewed-by: Jan Arve Sæther <jan-arve.saether@qt.io>
bb10
Frederik Gladhorn 2017-10-09 11:47:43 +02:00 committed by Liang Qi
parent 5eb508a317
commit 7a26582807
1 changed files with 1 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

2
src/widgets/accessible/simplewidgets.cpp
View File

@ -953,7 +953,7 @@ QAccessibleWindowContainer::QAccessibleWindowContainer(QWidget *w)
int QAccessibleWindowContainer::childCount() const
{
if (container()->containedWindow())
if (container()->containedWindow() && QAccessible::queryAccessibleInterface(container()->containedWindow()))
return 1;
return 0;
}