QVariant: ensure the type custom is registered on construction

I must have broken this in the 6.5 work I did for QMetaType and
QVariant, but I haven't searched which commit exactly did it. Our
QVariant tests are old and thus only checked the type ID, which meant
that they caused the registration by the act of asking for the ID in the
first place; this commit adds a couple of explicit checks for the type
registered by name before the ID.

Fixes: QTBUG-112205
Pick-to: 6.5 6.5.0
Change-Id: Idd5e1bb52be047d7b4fffffd174f1b14d90fd7a3
Reviewed-by: Fabian Kosmale <fabian.kosmale@qt.io>
bb10
Thiago Macieira 2023-03-23 07:02:42 -10:00
parent 4d90c4e74a
commit 8570e86fff
2 changed files with 11 additions and 0 deletions

View File

@ -806,6 +806,7 @@ QVariant::QVariant(const QVariant &p)
*/
QVariant::QVariant(QMetaType type, const void *copy) : d(type.iface())
{
type.registerType();
if (isValidMetaTypeForVariant(type.iface(), copy))
customConstruct(type.iface(), &d, copy);
else

View File

@ -1995,6 +1995,8 @@ void tst_QVariant::userType()
QVariant userVar;
userVar.setValue(data);
QVERIFY(QMetaType::fromName("MyType").isValid());
QCOMPARE(QMetaType::fromName("MyType"), QMetaType::fromType<MyType>());
QVERIFY(userVar.typeId() > QMetaType::User);
QCOMPARE(userVar.userType(), qMetaTypeId<MyType>());
QCOMPARE(userVar.typeName(), "MyType");
@ -2118,7 +2120,15 @@ void tst_QVariant::podUserType()
pod.a = 10;
pod.b = 20;
// one of these two must register the type
// (QVariant::fromValue calls QMetaType::fromType)
QVariant pod_as_variant = QVariant::fromValue(pod);
QMetaType mt = QMetaType::fromType<MyTypePOD>();
QCOMPARE(pod_as_variant.metaType(), mt);
QCOMPARE(pod_as_variant.metaType().name(), mt.name());
QCOMPARE(QMetaType::fromName(mt.name()), mt);
QCOMPARE_NE(pod_as_variant.typeId(), 0);
MyTypePOD pod2 = qvariant_cast<MyTypePOD>(pod_as_variant);
QCOMPARE(pod.a, pod2.a);