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Doc: fix name of return argument in prototype 

The documentation refers to it as \a ret, so call it ret rather than
just r.

Pick-to: 6.6 6.5
Fixes: QTBUG-116890
Change-Id: I12d8c3cfd33d5718d88794ca87bff996a27423ee
Reviewed-by: Safiyyah Moosa <safiyyah.moosa@qt.io>
Reviewed-by: Paul Wicking <paul.wicking@qt.io>
bb10
Volker Hilsheimer 2023-09-11 11:53:00 +02:00
parent ba2ebc24a1
commit fca11e0112
1 changed files with 2 additions and 2 deletions
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4
src/corelib/kernel/qmetaobject.cpp
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@ -1426,8 +1426,8 @@ printMethodNotFoundWarning(const QMetaObject *meta, QLatin1StringView name, qsiz
}
/*!
\fn template <typename ReturnArg, typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, Qt::ConnectionType type, QTemplatedMetaMethodReturnArgument<ReturnArg> r, Args &&... args)
\fn template <typename ReturnArg, typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, QTemplatedMetaMethodReturnArgument<ReturnArg> r, Args &&... args)
\fn template <typename ReturnArg, typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, Qt::ConnectionType type, QTemplatedMetaMethodReturnArgument<ReturnArg> ret, Args &&... args)
\fn template <typename ReturnArg, typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, QTemplatedMetaMethodReturnArgument<ReturnArg> ret, Args &&... args)
\fn template <typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, Qt::ConnectionType type, Args &&... args)
\fn template <typename... Args> bool QMetaObject::invokeMethod(QObject *obj, const char *member, Args &&... args)
\since 6.5